JEE Main 2021 · 16 March · evening · Numerical answer · +4 / −0
If one wants to remove all the mass of the earth to infinity in order to break it up completely.
The amount of energy that needs to be supplied will be x/5GM²/R where x is __________ (Round off to the Nearest Integer) (M is the mass of earth, R is the radius of earth, G is the gravitational constant)
Answer and solution
Answer 3
Solution
Physics sir · 4 steps
Build the earth one thin shell at a time; the energy to pull it apart is that same energy turned around.
- What we need. Scattering every bit of the earth to infinity takes energy equal to the size of its gravitational self-energy U. So find U for a uniform sphere of mass M and radius R.
- Add one shell. Suppose the sphere has grown to radius r. Its mass is m = Mr³/R³ and the potential at its surface is -Gm/r. Bring in a shell of mass dm = 3Mr²/R³ dr from infinity, and the energy changes by dU = -(Gm dm)/r = -3GM²/R⁶r⁴ dr.
U = -3GM²/R⁶∫₀^R r⁴ dr = -3GM²/R⁶·R⁵/5 = -3/5GM²/R
- Energy to supply. To break the earth up you must supply +3/5GM²/R. That is the energy that brings U back up to zero.
- So. Comparing with x/5GM²/R gives x = 3.
The common slip: 5. Treating the earth like a point mass M sitting at distance R from another mass M gives GM²/R, so x = 5. The mass is spread out, and the shells added early feel a weaker pull.
The idea to keep. A uniform solid sphere has self-energy -3/5GM²/R. A thin shell has -1/2GM²/R. To break up a body completely, supply the size of its self-energy.
Answer from the NTA final answer key. Solution by PrepWiser.