JEE Main 2024 · 6 April · morning · Single correct · +4 / −1
At -20°C and 1 atm pressure, a cylinder is filled with equal number of H₂,I₂ and HI molecules for the reaction H₂( g)+I₂( g)⇌ 2HI(g), the Kₚ for the process is x× 10⁻¹.
x= __________.
[Given : R=0.082 L atm K⁻¹ mol⁻¹]
- (a) 2
- (b) 1
- (c) 10
- (d) 0.01
Answer and solution
Answer (c) 10
Solution
Chemistry ma’am · 3 steps
Equal numbers of molecules mean equal partial pressures, so everything in Kₚ cancels to 1.
- Equal partial pressures. Partial pressure is proportional to the number of molecules. With equal numbers of H₂, I₂ and HI at a total of 1 atm, each gas has p = 1/3 atm.
Kₚ = p_(HI)²/(p_(H₂) p_(I₂)) = p²/(p × p) = 1
- Temperature drops out. For H₂ + I₂ ⇌ 2HI, Δ n_g = 2 - 2 = 0. So Kₚ = K_c(RT)⁰ = K_c. Neither -20°C nor R = 0.082 changes the answer, and both are given only to distract you.
- So. Kₚ = 1 = 10 × 10⁻¹, which gives x = 10, option (c).
The idea to keep. When Δ n_g = 0, the pressure terms cancel. Then Kₚ depends only on the ratio of amounts, and any T, P or R given in the question does not matter.
Answer from the NTA final answer key. Solution by PrepWiser.