JEE Main 2023 · 1 February · evening · Single correct · +4 / −1

The escape velocities of two planets A and B are in the ratio 1: 2. If the ratio of their radii respectively is 1: 3, then the ratio of acceleration due to gravity of planet A to the acceleration of gravity of planet B will be :

  1. (a) 4/3
  2. (b) 2/3
  3. (c) 3/4
  4. (d) 3/2
Answer and solution

Answer (c) 3/4

Solution

Physics sir · 3 steps

Write g in terms of escape velocity and radius, then take the ratio. The mass of the planet cancels out.

  1. Link v and g. Escape velocity is vₑ = √(2GM/R). Since g = GM/R², we have GM = gR², so vₑ = √2gR.

    vₑ² = 2gR ⇒ g = vₑ²/2R

  2. Take the ratio. g_A/g_B = (v_A/v_B)² × R_B/R_A = (1/2)² × 3/1.
  3. So. g_A/g_B = 1/4 × 3 = 3/4, which is option (c).

The idea to keep. Remember vₑ = √2gR. It lets you swap between escape velocity and surface gravity without ever needing the planet's mass.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 160 times in JEE Main since 2020. This question is from 2023.