JEE Main 2021 · 24 February · morning · Single correct · +4 / −1

If Y, K and η are the values of Young's modulus, bulk modulus and modulus of rigidity of any material respectively. Choose the correct relation for these parameters.

  1. (a) Y = 9Kη/(3K - η)N/m²
  2. (b) Y = 9Kη/(2η + 3K)N/m²
  3. (c) η = 3YK/(9K + Y)N/m²
  4. (d) K = Yη/(9η - 3Y)N/m²
Answer and solution

Answer (d) K = Yη/(9η - 3Y)N/m²

Solution

Physics sir · 3 steps

Write Y in terms of η and K through Poisson's ratio, then eliminate σ. Only one option survives.

  1. Two standard links. With Poisson's ratio σ, Young's modulus connects to the other two moduli as Y = 2η(1+σ) and Y = 3K(1-2σ).
  2. Eliminate σ. From the first, 2σ = Y/η - 2, so 1 - 2σ = 3 - Y/η = (3η - Y)/η. Put this into the second: Y = 3K(3η - Y)/η.

    9/Y = 3/η + 1/K ⇒ Y = 9Kη/(3K+η), K = Yη/(9η - 3Y), η = 3YK/(9K - Y)

    OptionGiven formCorrect formVerdict
    (a)Y = 9Kη/(3K - η)Y = 9Kη/(3K + η)sign wrong
    (b)Y = 9Kη/(2η + 3K)Y = 9Kη/(3K + η)extra factor 2
    (c)η = 3YK/(9K + Y)η = 3YK/(9K - Y)sign wrong
    (d)K = Yη/(9η - 3Y)K = Yη/(9η - 3Y)matches
  3. So. Solving Yη = 3K(3η - Y) for K gives K = Yη/(9η - 3Y), which is option (d).

The idea to keep. Remember 9/Y = 3/η + 1/K. Every other form, for Y, K or η, is just this one equation rearranged.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Elasticity

Asked about 90 times in JEE Main since 2020. This question is from 2021.