JEE Main 2025 · 3 April · morning · Single correct · +4 / −1

Which compound would give 3-methyl-6-oxoheptanal upon ozonolysis?

  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (a)

Solution

Chemistry ma’am · 3 steps

Join the two carbonyl carbons back into a C=C, then see where the second methyl sits on the ring.

  1. What ozonolysis does. Ozone cuts the C=C and turns each alkene carbon into a C=O. In a ring, this opens the ring into one chain with a carbonyl at each end. An alkene carbon carrying CH₃ becomes a ketone (-CO-CH₃), and one carrying H becomes -CHO.
  2. Rebuild the ring. 3-methyl-6-oxoheptanal is OHC-CH₂-CH(CH₃)-CH₂-CH₂-CO-CH₃. Join C1 (the CHO carbon) and C6 (the ketone carbon) with a double bond to get a six-membered ring. The ring methyl sits at C3, two carbons away from the CH= end, which puts it directly across from the methyl-bearing alkene carbon. That is 1,4-dimethylcyclohexene.
    OptionAlkeneOzonolysis product
    (a)1,4-dimethylcyclohexeneOHC-CH₂-CH(CH₃)-CH₂-CH₂-CO-CH₃, 3-methyl-6-oxoheptanal
    (b)1,6-dimethylcyclohexeneOHC-CH₂-CH₂-CH₂-CH(CH₃)-CO-CH₃, 5-methyl-6-oxoheptanal
    (c)1,3-dimethylcyclohexeneOHC-CH(CH₃)-CH₂-CH₂-CH₂-CO-CH₃, 2-methyl-6-oxoheptanal
    (d)1,5-dimethylcyclohexeneOHC-CH₂-CH₂-CH(CH₃)-CH₂-CO-CH₃, 4-methyl-6-oxoheptanal
  3. So. Only option (a), with the two methyls para to each other on the ring, opens up to give 3-methyl-6-oxoheptanal.

The idea to keep. To find the alkene from its ozonolysis product, erase the two C=O oxygens and join those carbons with a double bond. A keto-aldehyde from one molecule always means a ring alkene.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Hydrocarbons — Alkenes & Alkynes

Asked about 90 times in JEE Main since 2020. This question is from 2025.