JEE Main 2021 · 1 September · evening · Single correct · +4 / −1
Experimentally reducing a functional group cannot be done by which one of the following reagents?
- (a) Pt-C/H₂
- (b) Na/H₂
- (c) Pd-C/H₂
- (d) Zn/H₂O
Answer and solution
Answer (b) Na/H₂
Solution
Chemistry ma’am · 3 steps
A reducing system must actually deliver hydrogen to the substrate. Check which pair cannot do that.
- What reduction needs. Reducing a functional group means adding hydrogen to it. There are two ways to do that. One is H₂ gas activated on a metal catalyst. The other is a metal that gives electrons together with a proton source such as water, alcohol or acid.
Reagent How it works Reduces? Pt-C/H₂ H₂ adsorbs on Pt and adds across C=C or C=O (catalytic hydrogenation) Yes Na/H₂ Na is not a hydrogenation catalyst, and H₂ gas is not a proton source. Heated together they only form the salt NaH No Pd-C/H₂ H₂ activated on Pd (catalytic hydrogenation) Yes Zn/H₂O Zn gives electrons and water gives protons. It is used as the reductive workup in ozonolysis Yes - Why Na fails here. Sodium reduces things only when paired with a proton donor, as in Na/C₂H₅OH or Birch reduction with Na/liq. NH₃. With H₂ gas alone, nothing can put hydrogen onto the functional group.
- So. The reagent that cannot reduce a functional group is (b), Na/H₂.
The idea to keep. For reduction, look for H₂ on a catalyst metal (Pt, Pd, Ni) or a metal paired with a proton source (water, alcohol, acid, liquid ammonia). Na with H₂ gas fits neither pattern.
Answer from the NTA final answer key. Solution by PrepWiser.