JEE Main 2024 · 30 January · evening · Single correct · +4 / −1
When a potential difference V is applied across a wire of resistance R, it dissipates energy at a rate W. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the energy dissipation rate will become:
- (a) 1/2W
- (b) 4W
- (c) 1/4W
- (d) 2W
Answer and solution
Answer (b) 4W
Solution
Physics sir · 4 steps
Same voltage, so power goes as 1/R: find the new resistance and the rest follows.
- Start with W. With the full wire across V, the power is W = V²/R.
- Cut the wire. Resistance is proportional to length, so each half has resistance R/2.
- Join in parallel. Two equal resistors R/2 in parallel give 1/2 × R/2 = R/4.
W' = V²/(R/4) = 4 V²/R = 4W
- So. The resistance drops to a quarter on the same supply, so the energy dissipation rate becomes 4W, option (b).
The idea to keep. When the supply voltage is fixed, use P = V²/R: a smaller resistance means more power. Use P = I²R only when the current is the fixed quantity.
Answer from the NTA final answer key. Solution by PrepWiser.