JEE Main 2021 · 25 February · evening · Numerical answer · +4 / −0
The percentage increase in the speed of transverse waves produced in a stretched string if the tension is increased by 4%, will be __________%.
Answer and solution
Answer 2
Solution
Physics sir · 4 steps
Speed goes as the square root of tension, so a small percentage change in tension gets halved.
- Wave speed. For a stretched string with tension T and mass per unit length μ, the speed of a transverse wave is set by these two alone. The string is the same, so μ does not change.
v = √(T/μ) ⇒ (Δ v)/v × 100 = 1/2((Δ T)/T × 100)
- Put in numbers. The tension rises by 4%, so the speed rises by 1/2 × 4% = 2%.
- Exact check. Without the approximation, v₂/v₁ = √1.04 ≈ 1.0198. That is a rise of about 1.98%, which agrees with 2%.
- So. The speed of the transverse wave increases by 2%.
The common slip: 4. Treating v as directly proportional to T gives 4, not 2. Speed depends on the square root of tension, so halve the percentage.
The idea to keep. For y ∝ xⁿ, a small percentage change in x gives n times that percentage change in y. With v ∝ √T, take half the change in tension.
Answer from the NTA final answer key. Solution by PrepWiser.