JEE Main 2021 · 26 February · evening · Single correct · +4 / −1
Match List - I with List - II.
Choose the correct answer from the options given below :
| List - I | List - II | ||
|---|---|---|---|
| (a) | Sodium Carbonate | (i) | Deacon |
| (b) | Titanium | (ii) | Castner-Kellner |
| (c) | Chlorine | (iii) | van-Arkel |
| (d) | Sodium hydroxide | (iv) | Solvay |
- (a) (a) → (iv), (b) → (iii), (c) → (i), (d) → (ii)
- (b) (a) → (iv), (b) → (i), (c) → (ii), (d) → (iii)
- (c) (a) → (iii), (b) → (ii), (c) → (i), (d) → (iv)
- (d) (a) → (i), (b) → (iii), (c) → (iv), (d) → (ii)
Answer and solution
Answer (a) (a) → (iv), (b) → (iii), (c) → (i), (d) → (ii)
Solution
Chemistry ma’am · 2 steps
Ask what each process gives you at the very end, and the four pairs fall into place.
- Know the products. Each named process is known for one product. Match the product, not the raw materials, because some raw materials (like NaCl) show up in more than one process.
List - I Process What happens Sodium carbonate Solvay (iv) NaCl + NH₃ + CO₂ + H₂O → NaHCO₃ + NH₄Cl, then heating NaHCO₃ gives Na₂CO₃ Titanium van Arkel (iii) Impure Ti forms volatile TiI₄, which breaks down on a hot tungsten filament to pure Ti Chlorine Deacon (i) 4HCl + O₂ →(CuCl₂) 2Cl₂ + 2H₂O at about 723 K Sodium hydroxide Castner-Kellner (ii) Electrolysis of brine with a mercury cathode; the sodium amalgam reacts with water to give NaOH - So. The matching is sodium carbonate with Solvay, titanium with van Arkel, chlorine with Deacon and sodium hydroxide with Castner-Kellner, which is option (a).
The idea to keep. Learn each industrial process by its main product: Solvay for soda ash, Deacon for chlorine, Castner-Kellner for caustic soda, van Arkel for ultra-pure Ti or Zr.
Answer from the NTA final answer key. Solution by PrepWiser.