JEE Main 2022 · 26 July · evening · Numerical answer · +4 / −0
Suppose y=y(x) be the solution curve to the differential equation (d y)/(d x)-y=2-e⁻ˣ such that lim(x → ∞) y(x) is finite. If a and b are respectively the x - and y-intercepts of the tangent to the curve at x=0, then the value of a-4 b is equal to _____________.
Answer and solution
Answer 3
Solution
Maths sir · 5 steps
Solve the linear equation, then let the finite limit kill the Ceˣ term.
- Integrating factor. The equation has the form dy/dx + Py = Q with P = -1, so the integrating factor is e^(∫ -1 dx) = e⁻ˣ. Multiplying through turns the left side into an exact derivative.
d/dx(y e⁻ˣ) = 2e⁻ˣ - e⁻²ˣ ⇒ y e⁻ˣ = -2e⁻ˣ + 1/2e⁻²ˣ + C
- Use the limit. Multiply by eˣ to get y = -2 + 1/2e⁻ˣ + Ceˣ. As x → ∞, Ceˣ blows up unless C = 0. So y = -2 + 1/2e⁻ˣ.
- Tangent line. At x = 0, y(0) = -2 + 1/2 = -3/2 and y'(0) = -1/2. The tangent is y = -3/2 - 1/2x.
- Intercepts. Put x = 0: b = -3/2. Put y = 0: x = -3, so a = -3.
- So. a - 4b = -3 - 4(-3/2) = -3 + 6, which is 3.
The common slip: 15. Integrating -e⁻²ˣ as -1/2e⁻²ˣ instead of +1/2e⁻²ˣ gives the curve y = -2 - 1/2e⁻ˣ, intercepts a = 5 and b = -5/2, and the answer 15.
The idea to keep. A condition like a finite limit at infinity is an initial condition in disguise: any eˣ term must vanish, so its constant is 0. Keep the signs of the intercepts, they are not lengths.
Answer from the NTA final answer key. Solution by PrepWiser.