JEE Main 2023 · 8 April · morning · Single correct · +4 / −1
Which of the following represent the Freundlich adsorption isotherms?
Choose the correct answer from the options given below:
- (a) B, C, D only
- (b) A, B only
- (c) A, B, D only
- (d) A, C, D only
Answer and solution
Answer (c) A, B, D only
Solution
Chemistry ma’am · 2 steps
Write x/m = k p^(1/n) first, then check each graph's axes against it.
- The equation. Freundlich says the amount adsorbed per gram rises as a fractional power of pressure, with n > 1. Its log form is a straight line.
x/m = k p^(1/n) ⇒ log x/m = log k + 1/n log p
Graph Axes What Freundlich predicts Matches? A x/m vs p A curve from the origin that bends over, since 1/n < 1 Yes B log x/m vs log p A straight line, slope 1/n, intercept log k Yes C x/m vs c x/m = k c^(1/n): a curve through the origin, not a straight line with a positive intercept No D x/m vs p^(1/n) x/m = k × p^(1/n): a straight line through the origin with slope k Yes - So. Graphs A, B and D all follow from x/m = k p^(1/n). Graph C does not, so the answer is (c).
The idea to keep. For any isotherm graph, put the plotted axes into x/m = k p^(1/n). If the equation becomes y = mx or y = mx + c in those variables, the graph is a straight line. If it does not, the graph is a curve.
Answer from the NTA final answer key. Solution by PrepWiser.