JEE Main 2024 · 6 April · evening · Single correct · +4 / −1

When kinetic energy of a body becomes 36 times of its original value, the percentage increase in the momentum of the body will be :

  1. (a) 60%
  2. (b) 500%
  3. (c) 6%
  4. (d) 600%
Answer and solution

Answer (b) 500%

Solution

Physics sir · 3 steps

Momentum goes as the square root of kinetic energy, so 36 times the KE means only 6 times the momentum.

  1. Link p and K. With K = 1/2mv² and p = mv, you get K = p²/2m. For the same body the mass is fixed, so p is proportional to √K.

    p₂/p₁ = √(K₂/K₁) = √36 = 6

  2. Find the increase. The new momentum is 6p₁, so the increase is 6p₁ - p₁ = 5p₁. As a percentage of the original, that is 5p₁/p₁ × 100 = 500%.
  3. So. The momentum increases by 500%, which is option (b).

The idea to keep. For a fixed mass, p = √2mK. And percentage increase is (new minus old) over old: becoming 6 times means a 500% increase, not 600%.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 100 times in JEE Main since 2020. This question is from 2024.