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Rectilinear Motion revision notes

Every idea in the Rectilinear Motion chapter for JEE Main, with the usual mistakes and the fast methods. Topic 1 is open to everyone; sign in free to read all 37 and download the PDF.

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How we count: 7× asked means 7 past JEE Main questions in the PrepWiser bank needed that concept, and "last" is the latest year one appeared. ★ marks ideas asked 8 or more times.

Displacement, velocity and acceleration

Distance and displacement
8× asked, last 2026
∣Δr⃗ ∣≤distance|\Delta\vec r\,| \le \text{distance}
Displacement: straight line start to end, a vector. Distance: path length, never negative. Equal only for one-way straight motion.
  • Not the arc for displacement. Displacement is the straight chord between the end points. An extra full lap adds to the distance only; an extra half-lap also moves the end point to the diametrically opposite point.
Arc of a circle
5× asked, last 2025
distance=Rθ,∣Δr⃗ ∣=2Rsin⁡θ2\text{distance}=R\theta,\qquad |\Delta\vec r\,| = 2R\sin\frac{\theta}{2}
θ\theta in radians, the angle the arc makes at the centre. Quarter circle: R2R\sqrt2; half: 2R2R; full lap: 0.
RθR\theta∣Δr⃗ ∣|\Delta\vec r\,|θ\thetaOstartend
Distance: the arc RθR\theta. Displacement: the chord 2Rsin⁡θ22R\sin\frac{\theta}{2}
Average speed and average velocity
6× asked, last 2026
vˉ=total distancetotal time,v⃗avg=Δr⃗Δt\bar v=\frac{\text{total distance}}{\text{total time}},\qquad \vec v_{\text{avg}}=\frac{\Delta\vec r}{\Delta t}
Average speed ≥\ge magnitude of average velocity; equal only if the body never turns back on a straight line.
  • Not distance ÷ time for average velocity. Use displacement. A body that comes back to its start has zero average velocity, however far it went.
Equal distances or equal times
9× asked, last 2025
vˉequal x=2v1v2v1+v2,vˉequal t=v1+v22\bar v_{\text{equal } x}=\frac{2v_1v_2}{v_1+v_2},\qquad \bar v_{\text{equal } t}=\frac{v_1+v_2}{2}
One-way straight motion, so average speed = average velocity. Harmonic mean for equal distances, plain mean for equal times.
  • nn equal distances: vˉ=n/(1/v1+1/v2+⋯+1/vn)\bar v=n/(1/v_1+1/v_2+\dots+1/v_n). For three parts this is 3v1v2v3/(v1v2+v2v3+v3v1)3v_1v_2v_3/(v_1v_2+v_2v_3+v_3v_1).
  • Not (v1+v2)/2(v_1+v_2)/2 for equal distances, nor the plain mean of any phase speeds. More time is spent at the slower speed. Divide total distance by total time.
  • Quick method. Mixed trips: replace each equal-time pair by its plain mean first, then take the harmonic mean over the equal-distance parts. Check: v1=v2=vv_1=v_2=v must give vv.
Instantaneous velocity and acceleration
8× asked, last 2025
v=dxdt,a=dvdt=d2xdt2v=\frac{dx}{dt},\qquad a=\frac{dv}{dt}=\frac{d^2x}{dt^2}
Differentiate first, put in tt last. In 2D or 3D differentiate each component; a constant component gives zero.
vvaaThe body is
++++speeding up (va>0va>0)
−-−-speeding up (va>0va>0)
++−-slowing down (va<0va<0)
−-++slowing down (va<0va<0)
  • Speed =vx2+vy2+vz2=\sqrt{v_x^2+v_y^2+v_z^2}; a minus sign only gives direction, squares always add. Angle with an axis: tan⁡θ\tan\theta = other component ÷ component along that axis.
  • On a line: speeding up when vv and aa have the same sign (va>0va>0), slowing down when they are opposite (va<0va<0). The sign of aa alone does not decide it: a<0a<0 with v<0v<0 is speeding up.
  • Not x/tx/t. If x(0)=0x(0)=0 that is the average velocity from 0 to tt, not the velocity at tt. And not the coefficient in v=ktv=kt: that is the acceleration. Differentiate, then put in tt.
  • Not only the obvious t2t^2 term: expand brackets like (t−2)2(t-2)^2, since every hidden t2t^2 adds to aa. Keep signs when you put t=0t=0 for the initial velocity.
Average acceleration
2× asked, last 2023
a⃗avg=v⃗2−v⃗1Δt\vec a_{\text{avg}}=\frac{\vec v_2-\vec v_1}{\Delta t}
A vector change. If the body reverses (a bounce), the speeds add: ∣Δv∣=v1+v2|\Delta v|=v_1+v_2.

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Practise Rectilinear Motion

31 more concepts in 4 topics

Equations of motion (uniform acceleration), Motion graphs, Motion under gravity and Variable acceleration. Read the first part free. Sign in free with Google to read the rest and download the PDF.

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Equations of motion (uniform acceleration)

  • Equations of motion9×
  • Stopping distance and time4×
  • Displacement in the nth second4×
  • Starting from rest7×
  • Accelerate, then brake to rest3×
  • Velocity at the midpoint1×
  • Constant acceleration in a plane2×

Motion graphs

  • Position–time graph4×
  • Velocity–time graph10×
  • Acceleration–time graph3×
  • Graphs for constant acceleration2×
  • Velocity–position graph3×
  • Graph of v² against x2×

Motion under gravity

  • Free fall from rest10×
  • Thrown straight up8×
  • Thrown from a tower6×
  • Up, down and dropped from one point2×
  • Released from a moving body3×
  • Drops from a tap3×
  • Two bodies in free fall4×
  • Bouncing ball3×
  • Constant air drag1×
  • Smooth incline2×
  • Motion in stages2×

Variable acceleration

  • Acceleration from v(x)4×
  • Integrating v(t) and a(t)3×
  • Time given as a function of x2×
  • Implicit x–t relations2×
  • Turning points and extreme velocity4×
  • Force depending on x or v2×
  • Retardation depending on speed

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