JEE Main 2020 · 4 September · morning · Single correct · +4 / −1
The decreasing order of reactivity of the following organic molecules towards AgNO₃ solution is :
- (a) (B) > (A) > (C) > (D)
- (b) (A) > (B) > (C) > (D)
- (c) (A) > (B) > (D) > (C)
- (d) (C) > (D) > (A) > (B)
Answer and solution
Answer (a) (B) > (A) > (C) > (D)
Solution
Chemistry ma’am · 4 steps
AgNO₃ pulls off Cl⁻, so rank these by how stable the carbocation left behind is.
- What AgNO3 does. Ag⁺ grabs the chloride and AgCl precipitates, leaving a carbocation. This is an S_N1-type reaction, so the more stable the carbocation, the faster the precipitate forms.
- Aromatic cation. Removing Cl⁻ from (A) gives the cyclopropenyl cation. It is planar and cyclic with 2 π electrons, which fits 4n + 2 with n = 0. So it is aromatic and very stable.
Compound Carbocation formed Extra effect Stability (B) aromatic cyclopropenyl OCH₃ donates a lone pair (+M) highest (A) aromatic cyclopropenyl none very high (C) secondary, (CH₃)₂CH⁺ two methyls donate (+I, hyperconjugation) moderate (D) secondary CH₂NO₂ withdraws (−I) lowest - Compare the pairs. (B) has the same aromatic ring as (A), and the OCH₃ on the ring pushes electron density into the positive charge, so (B) beats (A). (C) and (D) are both secondary, but the NO₂ group in (D) pulls electrons away and destabilises the cation.
- So. The order of reactivity is (B) > (A) > (C) > (D), option (a).
The idea to keep. Reactivity with AgNO₃ means carbocation stability. Aromaticity beats everything, electron donors push it higher, and electron-withdrawing groups like NO₂ pull it down.
Answer from the NTA final answer key. Solution by PrepWiser.