JEE Main 2021 · 17 March · evening · Single correct · +4 / −1
The correct pair(s) of the ambident nucleophiles is(are)
(A) AgCN/KCN
(B) RCOOAg/RCOOK
(C) AgNO₂/KNO₂
(D) AgI/KI
- (a) (B) and (C) only
- (b) (B) only
- (c) (A) and (C) only
- (d) (A) only
Answer and solution
Answer (c) (A) and (C) only
Solution
Chemistry ma’am · 3 steps
Look at the anion, not the metal: ambident means two different atoms that can each donate the lone pair.
- What ambident means. An ambident nucleophile has two different donor atoms. Depending on which one attacks, you get two different products. The Ag or K salt only decides which atom ends up attacking.
Anion Donor atoms Products with R-X Ambident? CN⁻ C and N KCN gives R-CN, AgCN gives R-NC Yes RCOO⁻ two O atoms, equivalent by resonance only the ester RCOOR' No NO₂⁻ N and O KNO₂ gives R-O-N=O, AgNO₂ gives R-NO₂ Yes I⁻ only I only R-I No - Why carboxylate fails. In RCOO⁻ the negative charge is shared equally between two oxygen atoms. Whichever oxygen attacks, the bond formed is the same C–O bond, so there is only one product.
- So. Only cyanide and nitrite have two different donor atoms, so pairs (A) and (C) are ambident. The answer is (c).
The idea to keep. Call a nucleophile ambident only if two different atoms can attack and give two different products. Two identical resonance-equivalent atoms, like the O atoms of RCOO⁻, do not count.
Answer from the NTA final answer key. Solution by PrepWiser.