JEE Main 2024 · 27 January · evening · Single correct · +4 / −1

Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across A and B, their readings are V₁, V₂ and V₃. Choose the correct option.

JEE Main PYQ figure
  1. (a) V₁=V₂
  2. (b) V₁ ≠ V₃-V₂
  3. (c) V₁+V₂=V₃
  4. (d) V₁+V₂>V₃
Answer and solution

Answer (c) V₁+V₂=V₃

Solution

Physics sir · 4 steps

A voltmeter reads the potential difference across its own two ends, whatever its resistance is.

  1. Read the circuit. V₁ and V₂ are in series on the upper branch. V₃ sits alone on the lower branch. Both branches join the same two points, A and B.
  2. Series branch. On the upper branch, the drop from A to B is the sum of the drops across the two meters. Their resistances only decide how that total is split between them.
  3. Parallel branch. V₃ is connected straight across A and B, so it reads the full V_A - V_B. Parallel branches always have the same potential difference across them.

    V₁ + V₂ = V_A - V_B = V₃

  4. So. V₁ + V₂ = V₃ holds for any internal resistances, which is option (c).

The idea to keep. Different meter resistances change how the voltage is shared within a branch, never the total. Drops along a series path add up to the drop across any parallel path between the same two points.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Current Electricity

Asked about 250 times in JEE Main since 2020. This question is from 2024.