JEE Main 2021 · 26 February · morning · Numerical answer · +4 / −0
In an electrical circuit, a battery is connected to pass 20C of charge through it in a certain given time. The potential difference between two plates of the battery is maintained at 15V. The workdone by the battery is __________J.
Answer and solution
Answer 300
Solution
Physics sir · 3 steps
Voltage is work done per unit charge, so multiply the charge by the voltage and you have the work.
- What voltage means. A potential difference of 15 V means the battery does 15 J of work on every coulomb of charge it pushes through. So the work done is the charge multiplied by the potential difference.
W = qV
- Put in numbers. W = 20 C × 15 V = 300 J. The time is not needed, because the work depends only on how much charge moves and the voltage it moves through.
- So. The work done by the battery is 300 J.
The common slip: 0.75. Dividing instead of multiplying, W = V/q = 15/20, gives 0.75. One volt is one joule per coulomb, so multiply by the charge.
The idea to keep. Work done by a battery is W = qV. If time is given, it only matters when the question asks for power or current, not for the total work.
Answer from the NTA final answer key. Solution by PrepWiser.