JEE Main 2024 · 29 January · evening · Single correct · +4 / −1

On passing a gas, 'X', through Nessler's regent, a brown precipitate is obtained. The gas 'X' is

  1. (a) Cl₂
  2. (b) CO₂
  3. (c) NH₃
  4. (d) H₂ S
Answer and solution

Answer (c) NH₃

Solution

Chemistry ma’am · 3 steps

Nessler's reagent is the classic test for ammonia, so a brown precipitate points straight to NH₃.

  1. Know the reagent. Nessler's reagent is an alkaline solution of potassium tetraiodomercurate(II), K₂[HgI₄] in KOH. In salt analysis it is used to detect NH₄⁺: you heat the salt with NaOH and pass the gas given off through the reagent.
  2. Reaction with ammonia. Ammonia reacts with [HgI₄]²⁻ in the alkaline solution. It forms a brown precipitate called the iodide of Millon's base, HgO·Hg(NH₂)I.

    2K₂[HgI₄] + NH₃ + 3KOH → HgO·Hg(NH₂)I v + 7KI + 2H₂O

  3. So. The gas that gives a brown precipitate with Nessler's reagent is ammonia, option (c).

The idea to keep. Link each gas to its own test: NH₃ gives a brown precipitate with Nessler's reagent, CO₂ turns lime water milky, and H₂S turns lead acetate paper black.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Qualitative Analysis — Salt Analysis

Asked about 80 times in JEE Main since 2020. This question is from 2024.