JEE Main 2022 · 27 July · evening · Single correct · +4 / −1

Fe³⁺ cation gives a prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of :

  1. (a) [Fe(H₂ O)₆]₂[Fe(CN)₆]
  2. (b) Fe₂[Fe(CN)₆]₂
  3. (c) Fe₃[Fe(OH)₂(CN)₄]₂
  4. (d) Fe₄[Fe(CN)₆]₃
Answer and solution

Answer (d) Fe₄[Fe(CN)₆]₃

Solution

Chemistry ma’am · 4 steps

Prussian blue is ferric ferrocyanide: balance Fe³⁺ against [Fe(CN)₆]⁴⁻.

  1. Know the reagent. Potassium ferrocyanide is K₄[Fe(CN)₆]. In solution it gives the ferrocyanide ion [Fe(CN)₆]⁴⁻, with iron as Fe²⁺ and six CN⁻ ligands.
  2. Balance the charges. Each Fe³⁺ brings +3 and each ferrocyanide brings -4. The smallest neutral combination is 4 of the cation and 3 of the anion, because 4 × 3 = 3 × 4 = 12.

    4Fe³⁺ + 3[Fe(CN)₆]⁴⁻ → Fe₄[Fe(CN)₆]₃ v

  3. Name the product. Fe₄[Fe(CN)₆]₃ is ferric ferrocyanide, the deep blue precipitate called Prussian blue. It contains iron in both oxidation states: +3 outside the complex ion and +2 inside it.
  4. So. The Prussian blue precipitate is Fe₄[Fe(CN)₆]₃, option (d).

The idea to keep. For Prussian blue, think ferric ion plus ferrocyanide ion. Match +3 against -4: four iron ions outside and three complex ions, Fe₄[Fe(CN)₆]₃.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Qualitative Analysis — Salt Analysis

Asked about 80 times in JEE Main since 2020. This question is from 2022.