JEE Main 2024 · 8 April · evening · Single correct · +4 / −1
Match List I with List II
Choose the correct answer from the options given below :
| LIST I (Test) | LIST II (Identification) | ||
|---|---|---|---|
| A. | Bayer's test | I. | Phenol |
| B. | Ceric ammonium nitrate test | II. | Aldehyde |
| C. | Phthalein dye test | III. | Alcoholic-OH group |
| D. | Schiff's test | IV. | Unsaturation |
- (a) (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
- (b) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- (c) (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- (d) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Answer and solution
Answer (d) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Solution
Chemistry ma’am · 3 steps
Link each test to its reagent and what you see, and the functional group follows from that.
- Recall each reagent. Every named test uses a fixed reagent that reacts with one functional group. Write down the reagent and the observation for each test first. The match then follows directly.
Test Reagent What you see Detects A. Baeyer's test cold, dilute alkaline KMnO₄ pink colour disappears unsaturation (IV) B. Ceric ammonium nitrate test (NH₄)₂[Ce(NO₃)₆] yellow solution turns red alcoholic –OH (III) C. Phthalein dye test phthalic anhydride + conc. H₂SO₄, then NaOH coloured dye (pink for phenol) phenol (I) D. Schiff's test Schiff's reagent (decolourised rosaniline) pink colour comes back aldehyde (II) - Why B and C. In the phthalein test, phenol condenses with phthalic anhydride to form a phthalein dye, so it detects phenol. Ceric ammonium nitrate gives the red colour with alcohols, so it detects the alcoholic –OH group.
- So. The match is A-IV, B-III, C-I, D-II, which is option (d).
The idea to keep. For any named test, remember three things together: the reagent, the colour change, and the group. Phthalein dye means phenol, and ceric ammonium nitrate turning red means an alcohol.
Answer from the NTA final answer key. Solution by PrepWiser.