JEE Main 2024 · 8 April · evening · Single correct · +4 / −1

Match List I with List II
Choose the correct answer from the options given below :

LIST I (Test)LIST II (Identification)
A.Bayer's testI.Phenol
B.Ceric ammonium nitrate testII.Aldehyde
C.Phthalein dye testIII.Alcoholic-OH group
D.Schiff's testIV.Unsaturation
  1. (a) (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  2. (b) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  3. (c) (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  4. (d) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Answer and solution

Answer (d) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Solution

Chemistry ma’am · 3 steps

Link each test to its reagent and what you see, and the functional group follows from that.

  1. Recall each reagent. Every named test uses a fixed reagent that reacts with one functional group. Write down the reagent and the observation for each test first. The match then follows directly.
    TestReagentWhat you seeDetects
    A. Baeyer's testcold, dilute alkaline KMnO₄pink colour disappearsunsaturation (IV)
    B. Ceric ammonium nitrate test(NH₄)₂[Ce(NO₃)₆]yellow solution turns redalcoholic –OH (III)
    C. Phthalein dye testphthalic anhydride + conc. H₂SO₄, then NaOHcoloured dye (pink for phenol)phenol (I)
    D. Schiff's testSchiff's reagent (decolourised rosaniline)pink colour comes backaldehyde (II)
  2. Why B and C. In the phthalein test, phenol condenses with phthalic anhydride to form a phthalein dye, so it detects phenol. Ceric ammonium nitrate gives the red colour with alcohols, so it detects the alcoholic –OH group.
  3. So. The match is A-IV, B-III, C-I, D-II, which is option (d).

The idea to keep. For any named test, remember three things together: the reagent, the colour change, and the group. Phthalein dye means phenol, and ceric ammonium nitrate turning red means an alcohol.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 40 times in JEE Main since 2020. This question is from 2024.