JEE Main 2025 · 23 January · morning · Numerical answer · +4 / −1
A force f=x² y î+y² ĵ acts on a particle in a plane x+y=10. The work done by this force during a displacement from (0,0) to (4 m, 2 m) is _________ Joule (round off to the nearest integer)
Answer and solution
Answer 152
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