JEE Main 2022 · 26 June · evening · Single correct · +4 / −1

Arrange the four graphs in descending order of total work done; where W₁, W₂, W₃ and W₄ are the work done corresponding to figure a, b, c and d respectively.

JEE Main PYQ figure
JEE Main PYQ figure
JEE Main PYQ figure
JEE Main PYQ figure
  1. (a) W₃ > W₂ > W₁ > W₄
  2. (b) W₃ > W₂ > W₄ > W₁
  3. (c) W₂ > W₃ > W₄ > W₁
  4. (d) W₂ > W₃ > W₁ > W₄
Answer and solution

Answer (a) W₃ > W₂ > W₁ > W₄

Solution

Physics sir · 4 steps

Work is the signed area under the F–x graph, so add areas above the axis and subtract areas below it.

  1. Area rule. For a force that changes with position, W = ∫ F dx. On an F–x graph that is the area between the curve and the x-axis. Area above the axis counts as positive and area below counts as negative.
  2. Common first piece. In a, b and c the force rises in a straight line from -F at x = 0 to +F at x₁. So it crosses zero halfway, at x₀. The triangle below the axis and the triangle above it are the same size, and this part gives zero net work.
    FigurePieces of areaNet work
    a-1/2Fx₀ + 1/2F(x₁ - x₀), two equal triangles that cancelW₁ = 0
    bzero from the triangles, plus a rectangle F(x₂ - x₁) above the axisW₂ = F(x₂ - x₁) > 0
    cthe same as b, plus one more triangle above the axis after x₂W₃ > W₂
    dtriangles from +F down to -F cancel, then a rectangle -F(x₂ - x₁) below the axis, then a small triangle above itW₄ < 0
  3. Check figure d. The last triangle in d is shorter than F and narrower than x₂ - x₁. So it is much smaller than the rectangle below the axis, and the total stays negative.
  4. So. W₃ > W₂ > W₁ > W₄, with W₁ = 0 and W₄ negative. That is option (a).

The idea to keep. On an F–x graph, work is signed area. Area below the axis subtracts. A straight line from -F to +F gives equal triangles on both sides, so its net work is zero.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Work, Energy & Power

Asked about 100 times in JEE Main since 2020. This question is from 2022.