JEE Main 2020 · 2 September · morning · Single correct · +4 / −1
If AB₄ molecule is a polar molecule, a possible geometry of AB₄ is
- (a) Tetrahedral
- (b) see-saw
- (c) Square pyramidal
- (d) Square planar
Answer and solution
Answer (b) see-saw
Solution
Chemistry ma’am · 3 steps
Match each shape to its lone pairs; only a lone pair that breaks the symmetry leaves a net dipole.
- What polar needs. Four identical A–B bond dipoles cancel only when they are arranged symmetrically around A. A polar AB₄ needs a shape where they cannot cancel.
Geometry VSEPR type Example Dipoles cancel? Tetrahedral AB₄, no lone pair CH₄ yes, non-polar See-saw AB₄E, 1 lone pair SF₄ no, polar Square pyramidal AB₅E, 1 lone pair BrF₅ needs 5 B atoms, not an AB₄ shape Square planar AB₄E₂, 2 lone pairs XeF₄ yes, non-polar - Why see-saw. In see-saw, the lone pair sits in an equatorial position of the trigonal bipyramid. The four bonds are no longer symmetric, so their dipoles add up to a net dipole moment.
- So. A polar AB₄ molecule can be see-saw, option (b), like SF₄.
The idea to keep. Identical bonds placed symmetrically (tetrahedral, square planar, linear, trigonal planar, octahedral) give zero dipole. A lone pair that spoils the symmetry, as in see-saw, makes it polar.
Answer from the NTA final answer key. Solution by PrepWiser.