JEE Main 2021 · 18 March · morning · Single correct · +4 / −1

If the functions are defined as f(x) = √x and g(x) = √(1 - x), then what is the common domain of the following functions :
f + g, f - g, f/g, g/f, g - f where (f ± g)(x) = f(x) ± g(x),(f/g)x = f(x)/g(x)

  1. (a) 0 ≤ x ≤ 1
  2. (b) 0 ≤ x < 1
  3. (c) 0 < x < 1
  4. (d) 0 < x ≤ 1
Answer and solution

Answer (c) 0 < x < 1

Solution

Maths sir · 3 steps

Find each domain on its own, then keep only the values of x that work for all five functions.

  1. Individual domains. f(x) = √x needs x ≥ 0, and g(x) = √(1 - x) needs x ≤ 1. Both are defined together only on [0, 1].
  2. Quotients add a condition. Sums and differences need nothing extra. A quotient also needs a denominator that is not zero, and g(1) = 0 while f(0) = 0.
    FunctionExtra conditionDomain
    f + g, f - g, g - fnone[0, 1]
    f/gg(x) ≠ 0, so x ≠ 1[0, 1)
    g/ff(x) ≠ 0, so x ≠ 0(0, 1]
  3. So. The common domain is [0, 1] ∩ [0, 1) ∩ (0, 1] = (0, 1), that is, 0 < x < 1. The answer is (c).

The idea to keep. For combined functions, start with the overlap of the individual domains. Then remove every point where a denominator becomes zero. A common domain is the intersection of all of them.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Functions (Advanced)

Asked about 70 times in JEE Main since 2020. This question is from 2021.