JEE Main 2025 · 28 January · evening · Single correct · +4 / −1

Let f:[0,3] → A be defined by f(x)=2 x³-15 x²+36 x+7 and g:[0, ∞) → B be defined by g(x)=x²⁰²⁵/(x²⁰²⁵+1), If both the functions are onto and S={ x ∈ Z ; x ∈ A or x ∈ B }, then n(S) is equal to :

  1. (a) 29
  2. (b) 31
  3. (c) 30
  4. (d) 36
Answer and solution

Answer (c) 30

Solution

Maths sir · 4 steps

Onto means A and B are exactly the ranges, so find each range and count the integers in them.

  1. Critical points of f. f'(x) = 6x² - 30x + 36 = 6(x-2)(x-3). So f increases on [0,2] and decreases on [2,3].
  2. Range of f. f(0) = 7, f(2) = 16 - 60 + 72 + 7 = 35 and f(3) = 54 - 135 + 108 + 7 = 34. So A = [7, 35], which holds the 29 integers from 7 to 35.

    g(x) = x²⁰²⁵/(x²⁰²⁵+1) = 1 - 1/(x²⁰²⁵+1)

  3. Range of g. At x = 0, g = 0. As x grows, g increases towards 1 but never reaches it. So B = [0, 1), and its only integer is 0.
  4. So. A and B do not overlap, so n(S) = 29 + 1 = 30, option (c).

The idea to keep. For a cubic on a closed interval, check the values at the endpoints and at the critical points inside it. For a function like t/(t+1), watch which end is reached and which is only approached.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Functions (Advanced)

Asked about 70 times in JEE Main since 2020. This question is from 2025.