JEE Main 2022 · 29 June · evening · Numerical answer · +4 / −0

The number of chiral alcohol(s) with molecular formula C₄H₁₀O is ________.

Answer and solution

Answer 1

Solution

Chemistry ma’am · 3 steps

Draw all four butanols, then hunt for one carbon holding four different groups.

  1. List the alcohols. C₄H₁₀O fits CₙH₂ₙ₊₂O, so it is saturated with no ring. With a four-carbon skeleton and one -OH, there are exactly four alcohols.
  2. Test for chirality. A molecule like this is chiral when one carbon carries four different groups. Two identical groups on that carbon rule it out.
    AlcoholStructureGroups on the key carbonChiral?
    Butan-1-olCH₃CH₂CH₂CH₂OHC1: H, H, OH, C₃H₇No
    Butan-2-olCH₃CH(OH)CH₂CH₃C2: H, OH, CH₃, C₂H₅, all differentYes
    2-Methylpropan-1-ol(CH₃)₂CHCH₂OHC2: H, CH₃, CH₃, CH₂OHNo
    2-Methylpropan-2-ol(CH₃)₃COHC2: OH, CH₃, CH₃, CH₃No
  3. So. Only butan-2-ol has a stereocentre, so the number of chiral alcohols is 1.

The common slip: 2. Counting the two enantiomers of butan-2-ol separately gives 2, but the question asks for chiral alcohols, so that pair is one compound.

The idea to keep. For chirality counts, first list every structural isomer, then check each carbon for four different groups. Two identical groups, such as two CH₃ or two H, rule that carbon out.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 180 times in JEE Main since 2020. This question is from 2022.