JEE Main 2020 · 6 September · evening · Single correct · +4 / −1

Which of the following compounds can be prepared in good yield by Gabriel phthalimide synthesis?

  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d) CH₃—CH₂—NHCH₃
Answer and solution

Answer (b)

Solution

Chemistry ma’am · 3 steps

Gabriel gives only primary amines from S_N2-friendly halides, so look for RCH₂NH₂.

  1. How Gabriel works. Phthalimide with KOH gives potassium phthalimide. Its N⁻ attacks an alkyl halide by S_N2, and hydrolysis (or hydrazine) then releases R-NH₂.

    C₆H₄(CO)₂N⁻K⁺ + R-X → C₆H₄(CO)₂N-R →(hydrolysis) R-NH₂

  2. Two conditions. Only one R group attaches to nitrogen, so the product is always a primary amine. The halide must undergo S_N2, so aryl halides do not work.
    OptionCompoundNeeded halideGabriel works?
    (a)Aniline, C₆H₅NH₂C₆H₅Cl, aryl halideNo, there is no S_N2 on an aryl carbon
    (b)Benzylamine, C₆H₅CH₂NH₂C₆H₅CH₂Cl, benzyl halideYes, fast S_N2 gives a primary amine
    (c)C₆H₅CH₂CONH₂not an amine at allNo, it is an amide
    (d)CH₃CH₂NHCH₃would need two R groups on NNo, it is a secondary amine
  3. So. Benzylamine comes from benzyl chloride in good yield, so the answer is (b).

The idea to keep. Gabriel synthesis means primary amines from halides that undergo S_N2. Aryl amines, secondary or tertiary amines, and amides are all out.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Amines & Diazonium Salts

Asked about 170 times in JEE Main since 2020. This question is from 2020.