JEE Main 2025 · 7 April · evening · Single correct · +4 / −1
An object with mass 500 g moves along x-axis with speed v = 4√x m/s. The force acting on the object is :
- (a) 8 N
- (b) 4 N
- (c) 5 N
- (d) 6 N
Answer and solution
Answer (b) 4 N
Solution
Physics sir · 3 steps
Speed is given as a function of position, so use a = vdv/dx to get the acceleration.
- Square the speed. From v = 4√x we get v² = 16x. Squaring first removes the square root and makes the derivative easy.
a = vdv/dx = 1/2d(v²)/dx = 1/2 × 16 = 8 m s⁻²
- Constant acceleration. The acceleration does not depend on x, so it is the same everywhere. This matches v² = 2ax for a body starting from rest at x = 0: here 2a = 16.
- So. With m = 500 g = 0.5 kg, the force is F = ma = 0.5 × 8 = 4 N, option (b).
The idea to keep. When v is given in terms of x, use a = vdv/dx, or the shortcut a = 1/2d(v²)/dx. Any v² ∝ x means constant acceleration.
Answer from the NTA final answer key. Solution by PrepWiser.