JEE Main 2023 · 24 January · evening · Single correct · +4 / −1

K₂Cr₂O₇ paper acidified with dilute H₂SO₄ turns green when exposed to :

  1. (a) Sulphur dioxide
  2. (b) Sulphur trioxide
  3. (c) Hydrogen sulphide
  4. (d) Carbon dioxide
Answer and solution

Answer (a) Sulphur dioxide

Solution

Chemistry ma’am · 2 steps

Green means Cr³⁺, so look for the gas that can reduce orange dichromate.

  1. What green means. In dichromate chromium is +6, and the Cr₂O₇²⁻ ion is orange. When it is reduced to Cr³⁺ (+3), the colour turns green. So the gas must be a reducing agent.
    GasOxidation state of S or CCan it reduce dichromate?
    SO₂S is +4, can rise to +6Yes: the paper turns green, with no other change
    SO₃S is +6, already its highestNo
    H₂SS is -2Yes, but it also deposits sulphur. Its standard test is lead acetate paper turning black
    CO₂C is +4, already its highestNo

    Cr₂O₇²⁻ + 3SO₂ + 2H⁺ → 2Cr³⁺ + 3SO₄²⁻ + H₂O

  2. So. Acidified dichromate paper turning green is the standard lab test for sulphur dioxide, which is option (a).

The idea to keep. Orange to green in dichromate always means Cr⁶⁺ was reduced to Cr³⁺. A gas whose central atom is already in its highest oxidation state cannot do it.

Answer from the NTA final answer key. Solution by PrepWiser.

Study d & f Block Elements

Asked about 170 times in JEE Main since 2020. This question is from 2023.