JEE Main 2021 · 1 September · evening · Single correct · +4 / −1

Following plots show magnetization (M) vs magnetizing field (H) and magnetic susceptibility (χ) vs temperature (T) graph :
Which of the following combination will be represented by a diamagnetic material?

JEE Main PYQ figure
  1. (a) (a), (c)
  2. (b) (a), (d)
  3. (c) (b), (d)
  4. (d) (b), (c)
Answer and solution

Answer (a) (a), (c)

Solution

Physics sir · 3 steps

A diamagnet pushes back: M opposes H, so χ is negative, and it does not care about temperature.

  1. Sign of magnetization. In a diamagnetic material the induced magnetization points opposite to the applied field. So M = χ H with χ < 0, and the M vs H graph is a straight line through the origin with a negative slope.
  2. Temperature dependence. Diamagnetism comes from orbital motion responding to the field, not from aligning permanent dipoles. Thermal agitation has nothing to disturb, so χ stays negative and constant as T changes.
    GraphWhat it showsMaterial
    (a)M vs H line with negative slope, so χ < 0diamagnetic
    (b)M vs H line with positive slope, so χ > 0paramagnetic
    (c)χ negative and independent of Tdiamagnetic
    (d)χ positive and falling as 1/Tparamagnetic (Curie law)
  3. So. The diamagnetic pair is graphs (a) and (c), which is option (a).

The idea to keep. Read the sign first: negative χ means diamagnetic. Then read the trend: only paramagnets follow Curie's law χ ∝ 1/T; a diamagnet's χ is flat in temperature.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Magnetism & Matter

Asked about 60 times in JEE Main since 2020. This question is from 2021.