JEE Main 2024 · 9 April · evening · Single correct · +4 / −1
Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning :
- (a) Λₘ-Λₘ°+AC^(1/2)=0
- (b) Λₘ² C+Kₐ Λₘ^(o²)-Kₐ Λₘ Λₘ°=0
- (c) Λₘ-Λₘ°-AC^(1/2)=0
- (d) Λₘ² C-Kₐ Λₘ^(° 2)+Kₐ Λₘ Λₘ°=0
Answer and solution
Answer (d) Λₘ² C-Kₐ Λₘ^(° 2)+Kₐ Λₘ Λₘ°=0
Solution
Chemistry ma’am · 4 steps
For a weak electrolyte, put α = Λₘ/Λₘ° into Ostwald's dilution law and rearrange.
- Degree of dissociation. A weak electrolyte is only partly ionised. By Kohlrausch's idea, its degree of dissociation is α = Λₘ/Λₘ°.
- Ostwald's dilution law. For HA ⇌ H⁺ + A⁻ at concentration C, Kₐ = Cα²/(1-α). Substitute α and multiply top and bottom by Λₘ^(° 2).
Kₐ = CΛₘ²/Λₘ°(Λₘ° - Λₘ)
- Cross-multiply. KₐΛₘ^(° 2) - KₐΛₘΛₘ° = CΛₘ². Moving everything to one side gives Λₘ² C - KₐΛₘ^(° 2) + KₐΛₘΛₘ° = 0.
- So. This matches option (d). The √C equations in (a) and (c) describe strong electrolytes, not weak ones.
The idea to keep. Weak electrolyte: combine α = Λₘ/Λₘ° with Kₐ = Cα²/(1-α). The Λₘ = Λₘ° - A√C law is only for strong electrolytes.
Answer from the NTA final answer key. Solution by PrepWiser.