JEE Main 2025 · 3 April · evening · Single correct · +4 / −1

For electrons in ' 2 s ' and ' 2 p ' orbitals, the orbital angular momentum values, respectively are:

  1. (a) 0 and √6 h/(2 π)
  2. (b) 0 and √2 h/(2 π)
  3. (c) √2 h/(2 π) and 0
  4. (d) h/(2 π) and √2 h/(2 π)
Answer and solution

Answer (b) 0 and √2 h/(2 π)

Solution

Chemistry ma’am · 4 steps

Orbital angular momentum depends only on l, so find l for each orbital and use √l(l+1).

  1. The formula. The orbital angular momentum of an electron is set by the azimuthal quantum number l, not by n.

    L = √l(l+1) h/2π

  2. 2s electron. An s orbital has l = 0, so L = √(0 × 1) h/2π = 0.
  3. 2p electron. A p orbital has l = 1, so L = √(1 × 2) h/2π = √2 h/2π.
  4. So. The values are 0 and √2 h/2π, which is option (b).

The idea to keep. Orbital angular momentum is √l(l+1) h/2π. It uses l only: every s electron gives 0, every p gives √2, every d gives √6, whatever the value of n.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Atomic Structure

Asked about 170 times in JEE Main since 2020. This question is from 2025.