JEE Main 2020 · 4 September · evening · Numerical answer · +4 / −0

The speed verses time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be________.

JEE Main PYQ figure
Answer and solution

Answer 20

Solution

Physics sir · 3 steps

On a speed-time graph, distance is the area under the line, and here that area is one triangle.

  1. Read the graph. The speed rises in a straight line from 0 at t = 0 to 8 m s⁻¹ at t = 5 s. Speed is never negative, so the area under the graph gives the distance.
  2. Shape of the area. The region between the line and the time axis is a right triangle. Its base is 5 s and its height is 8 m s⁻¹.

    d = 1/2 × 5 s × 8 m s⁻¹ = 20 m

  3. So. The particle travels 20 m in the first 5 s.

The common slip: 40. Multiplying the final speed by the time without the factor 1/2 gives 40 m. The particle was slower than 8 m s⁻¹ for the whole 5 s, so use the average speed, 4 m s⁻¹.

The idea to keep. Area under a speed-time graph is distance. Break it into triangles and rectangles. If speed changes uniformly, use average speed times time.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Rectilinear Motion

Asked about 110 times in JEE Main since 2020. This question is from 2020.