JEE Main 2024 · 31 January · morning · Numerical answer · +4 / −1

The number of species from the following in which the central atom uses sp³ hybrid orbitals in its bonding is __________.
NH₃, SO₂, SiO₂, BeCl₂, CO₂, H₂ O, CH₄, BF₃

Answer and solution

Answer 4

Solution

Chemistry ma’am · 3 steps

Count sigma bonds plus lone pairs on the centre; four means sp3. Watch SiO₂, it is not like CO₂.

  1. Steric number. Add the sigma bonds and the lone pairs on the central atom. A total of 2 means sp, 3 means sp², and 4 means sp³. Pi bonds do not count.
  2. Silica is a network. SiO₂ is not a small linear molecule. Silicon does not form stable Si=O double bonds, so each Si bonds to four O atoms by single bonds in a giant 3D network of SiO₄ tetrahedra.
    SpeciesSigma bondsLone pairsHybridisation
    NH₃31sp³
    SO₂21sp²
    SiO₂40sp³
    BeCl₂20sp
    CO₂20sp
    H₂O22sp³
    CH₄40sp³
    BF₃30sp²
  3. So. The central atom is sp³ in NH₃, SiO₂, H₂O and CH₄, so the answer is 4.

The common slip: 3. Treating SiO₂ as linear like CO₂ makes Si sp and gives 3, not 4.

The idea to keep. Hybridisation comes from sigma bonds plus lone pairs on the central atom, never from the formula's look. For a network solid like SiO₂, count the real bonds around each atom.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Chemical Bonding & Molecular Structure

Asked about 210 times in JEE Main since 2020. This question is from 2024.