JEE Main 2024 · 5 April · evening · Single correct · +4 / −1

Match List I with List II :
Choose the correct answer from the options given below :

LIST I EM-WaveLIST II Wavelength Range
A.Infra-redI.<10⁻³ nm
B.UltravioletII.400 nm to 1 nm
C.X-raysIII.1 mm to 700 nm
D.Gamma raysIV.1 nm to 10⁻³ nm
  1. (a) (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  2. (b) (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  3. (c) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  4. (d) (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Answer and solution

Answer (b) (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Solution

Physics sir · 3 steps

Line the four waves up from longest to shortest wavelength, and the four ranges fall into place.

  1. Order the waves. Going from long to short wavelength, the order is infra-red, then visible light, then ultraviolet, then X-rays, then gamma rays. Visible light sits between about 700 nm and 400 nm, and that is the anchor.
  2. Order the ranges. Sort List II the same way: 1 mm to 700 nm is the longest, then 400 nm to 1 nm, then 1 nm to 10⁻³ nm, and finally less than 10⁻³ nm.
    WaveWhere it sitsRangeMatch
    Infra-redjust longer than red light (700 nm)1 mm to 700 nm(A)-(III)
    Ultravioletjust shorter than violet light (400 nm)400 nm to 1 nm(B)-(II)
    X-raysshorter than UV1 nm to 10⁻³ nm(C)-(IV)
    Gamma raysshortest of all< 10⁻³ nm(D)-(I)
  3. So. The matching is (A)-(III), (B)-(II), (C)-(IV), (D)-(I), which is option (b).

The idea to keep. Remember visible light as 400 to 700 nm. Infra-red is just beyond red, ultraviolet is just beyond violet, and X-rays and then gamma rays keep getting shorter.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Electromagnetic Waves

Asked about 130 times in JEE Main since 2020. This question is from 2024.