The incorrect statement from the following for borazine is :

Solution

Chemistry ma’am · 3 steps

Borazine is inorganic benzene; banana bonds belong to its boron cousin diborane, not to borazine.

1. Know the structure. Borazine, B₃N₃H₆, is a flat six-membered ring of alternating B and N atoms. Each B and each N carries one H, just as each C in benzene does.
2. Source of delocalisation. Each N gives its lone pair into the empty p orbital of the neighbouring B. This spreads the π electrons around the ring, though less evenly than in benzene because N is more electronegative than B.

   Statement	True for borazine?	Reason
   (a) Reacts with water	Yes	Water attacks the polar B–N bonds: B₃N₃H₆ + 9H₂O → 3B(OH)₃ + 3NH₃ + 3H₂
   (b) Cyclic	Yes	A six-membered B–N ring, like benzene
   (c) Electronic delocalisation	Yes	N lone pairs are shared into the empty p orbitals of B
   (d) Banana bonds	No	Every bond is a normal two-centre two-electron bond. The 3c–2e B–H–B banana bonds are found in B₂H₆

3. So. Statements (a), (b) and (c) are all true. The incorrect statement is (d), because borazine has no banana bonds.

The idea to keep. Banana bonds (3c–2e B–H–B bridges) belong to diborane. Borazine is benzene-like: a cyclic, delocalised B–N ring, but more reactive than benzene because the B–N bond is polar.

Answer from the NTA final answer key. Solution by PrepWiser.