JEE Main 2021 · 25 July · evening · Single correct · +4 / −1
Which among the following is the strongest acid ?
- (a) CH₃CH₂CH₂CH₃
- (b)
- (c)
- (d)
Answer and solution
Answer (d)
Solution
Chemistry ma’am · 4 steps
For hydrocarbon acids, remove an H⁺ and check the anion: an aromatic anion makes the strongest acid.
- Judge the anion. A hydrocarbon behaves as an acid by losing H⁺ from a C–H bond. The more stable the carbanion left behind, the stronger the acid. So compare the anion each compound gives.
- Aromaticity test. A planar, cyclic, fully conjugated anion with (4n+2) π electrons is aromatic and very stable. With 4n π electrons it is antiaromatic and very unstable.
Compound Anion formed π electrons in ring Anion stability (a) butane butyl (secondary) carbanion none no stabilisation, pKₐ ≈ 50 (b) toluene benzyl anion charge spread by resonance moderate, pKₐ ≈ 41 (c) cyclopropene cyclopropenyl anion 4 (4n, n = 1) antiaromatic, very unstable (d) cyclopentadiene cyclopentadienyl anion 6 (4n+2, n = 1) aromatic, pKₐ ≈ 16 - Why d wins. Removing H⁺ from the CH₂ of cyclopentadiene leaves a lone pair in a p orbital. That lone pair joins the four π electrons of the two double bonds, giving a 6π aromatic ring with the charge shared equally over all five carbons.
- So. Cyclopentadiene, option (d), is the strongest acid. Its pKₐ of about 16 is close to that of water, far lower than any other hydrocarbon here.
The idea to keep. When a C–H acid is asked, draw the carbanion and count its ring π electrons. Aromatic (4n+2) anion means a strong acid; antiaromatic (4n) anion means a very weak one.
Answer from the NTA final answer key. Solution by PrepWiser.