JEE Main 2025 · 4 April · evening · Single correct · +4 / −1
In which pairs, the first ion is more stable than the second?
- (a) (A) & (B) only
- (b) (B) & (D) only
- (c) (A) & (C) only
- (d) (B) & (C) only
Answer and solution
Answer (a) (A) & (B) only
Solution
Chemistry ma’am · 2 steps
In each pair, ask what feeds or soaks up the charge: lone pairs and π bonds beat plain alkyl groups.
- The rules. A carbocation is stabilised by groups that push electrons in: a lone pair by resonance (+M) is strongest, then a C=C by resonance, then alkyl groups by hyperconjugation. A carbanion is stabilised by groups that pull electrons out, such as an aryl ring carrying NO₂.
Pair First ion Second ion First more stable? (A) Cation with OMe on C⁺: the O lone pair gives +M, so every atom gets a full octet Cation with Me on C⁺: only hyperconjugation Yes (B) Benzylic carbanion: the charge spreads into the ring and onto the o-NO₂ oxygens Benzylic carbocation: the o-NO₂ pulls electrons away (−I, −M) and destabilises it Yes (C) Primary cyclohexylmethyl cation: weak hyperconjugation only Allylic cation: the ring C=C delocalises the + charge No (D) tert-Butyl cation: hyperconjugation only Cation with OMe on C⁺: +M from O No - So. The first ion wins only in (A) and (B), so the answer is (a).
The idea to keep. Cations want electron donors: +M lone pairs first, then π bonds, then alkyl hyperconjugation. Anions want electron acceptors like NO₂. The same group can stabilise one ion and destabilise the other.
Answer from the NTA final answer key. Solution by PrepWiser.