JEE Main 2025 · 4 April · evening · Single correct · +4 / −1

In which pairs, the first ion is more stable than the second?

JEE Main PYQ figure
  1. (a) (A) & (B) only
  2. (b) (B) & (D) only
  3. (c) (A) & (C) only
  4. (d) (B) & (C) only
Answer and solution

Answer (a) (A) & (B) only

Solution

Chemistry ma’am · 2 steps

In each pair, ask what feeds or soaks up the charge: lone pairs and π bonds beat plain alkyl groups.

  1. The rules. A carbocation is stabilised by groups that push electrons in: a lone pair by resonance (+M) is strongest, then a C=C by resonance, then alkyl groups by hyperconjugation. A carbanion is stabilised by groups that pull electrons out, such as an aryl ring carrying NO₂.
    PairFirst ionSecond ionFirst more stable?
    (A)Cation with OMe on C⁺: the O lone pair gives +M, so every atom gets a full octetCation with Me on C⁺: only hyperconjugationYes
    (B)Benzylic carbanion: the charge spreads into the ring and onto the o-NO₂ oxygensBenzylic carbocation: the o-NO₂ pulls electrons away (−I, −M) and destabilises itYes
    (C)Primary cyclohexylmethyl cation: weak hyperconjugation onlyAllylic cation: the ring C=C delocalises the + chargeNo
    (D)tert-Butyl cation: hyperconjugation onlyCation with OMe on C⁺: +M from ONo
  2. So. The first ion wins only in (A) and (B), so the answer is (a).

The idea to keep. Cations want electron donors: +M lone pairs first, then π bonds, then alkyl hyperconjugation. Anions want electron acceptors like NO₂. The same group can stabilise one ion and destabilise the other.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 180 times in JEE Main since 2020. This question is from 2025.