JEE Main 2021 · 26 February · evening · Single correct · +4 / −1

A tuning fork A of unknown frequency produces 5 beats/s with a fork of known frequency 340 Hz. When fork A is filed, the beat frequency decreases to 2 beats/s. What is the frequency of fork A?

  1. (a) 335 Hz
  2. (b) 345 Hz
  3. (c) 338 Hz
  4. (d) 342 Hz
Answer and solution

Answer (a) 335 Hz

Solution

Physics sir · 3 steps

Filing a fork raises its pitch, so A must start below 340 Hz for the beats to fall.

  1. Two candidates. Beat frequency is the difference of the two frequencies, so |f_A - 340| = 5. That gives f_A = 335 Hz or f_A = 345 Hz.
  2. Effect of filing. Filing removes metal from the prongs, so they get lighter and vibrate faster. Filing always increases the frequency of a fork.
    Starting f_AAfter filingBeats with 340 HzMatches?
    335 Hzrises towards 340, reaches 338 Hz5 → 2, decreasesyes
    345 Hzrises away from 3405 → more than 5, increasesno
  3. So. Only a fork starting below 340 Hz can have its beats drop when filed. The frequency of fork A is 335 Hz, option (a).

The idea to keep. Beats give two possible frequencies. Then ask which way the change moves the fork: filing raises frequency, loading with wax lowers it. Keep the root whose beats change the way the question says.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 40 times in JEE Main since 2020. This question is from 2021.