JEE Main 2024 · 29 January · evening · Single correct · +4 / −1

The product A formed in the following reaction is

JEE Main PYQ figure
  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (c)

Solution

Chemistry ma’am · 3 steps

Two stages here: first turn -NH₂ into -N₂⁺, then let CuCl swap that N₂ for Cl.

  1. Diazotisation. NaNO₂ and HCl give nitrous acid. At 0 °C it converts aniline into benzenediazonium chloride, C₆H₅N₂⁺Cl⁻. The cold keeps this salt from breaking down.
  2. Sandmeyer reaction. Cu₂Cl₂, which is CuCl, replaces the -N₂⁺ group with Cl. Nitrogen gas leaves, and the Cl takes the exact ring position where the NH₂ group was.

    C₆H₅NH₂ →(NaNO₂, HCl, 0 °C) C₆H₅N₂⁺Cl⁻ →(Cu₂Cl₂) C₆H₅Cl + N₂ ↑

  3. So. A is chlorobenzene, C₆H₅Cl, with one Cl on the ring and no nitrogen left. That is option (c).

The idea to keep. In a Sandmeyer reaction the diazonium group is swapped out. The new group sits exactly where NH₂ was, and the nitrogen is lost as N₂ gas.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Amines & Diazonium Salts

Asked about 170 times in JEE Main since 2020. This question is from 2024.