JEE Main 2025 · 23 January · morning · Single correct · +4 / −1

Which among the following react with Hinsberg's reagent?
A.
B.
C.CH₃-NH₂
D. N(CH₃)₃
E.
Choose the correct answer from the options given below :

JEE Main PYQ figure
JEE Main PYQ figure
JEE Main PYQ figure
  1. (a) A, C and E only
  2. (b) A, B and E only
  3. (c) C and D only
  4. (d) B and D only
Answer and solution

Answer (a) A, C and E only

Solution

Chemistry ma’am · 2 steps

Hinsberg's reagent needs an N–H to replace, so look for a hydrogen on nitrogen in each structure.

  1. What the reagent does. Hinsberg's reagent is benzenesulphonyl chloride, C₆H₅SO₂Cl. The amine nitrogen attacks the sulphur and loses an H from nitrogen along with Cl as HCl, giving a sulphonamide. No H on nitrogen means no reaction.

    R-NH₂ + C₆H₅SO₂Cl → C₆H₅SO₂NHR + HCl

    CompoundTypeH on NReacts?
    A: aniline, C₆H₅NH₂1°2yes
    B: N,N-dimethylaniline, C₆H₅N(CH₃)₂3°0no
    C: methylamine, CH₃NH₂1°2yes
    D: trimethylamine, N(CH₃)₃3°0no
    E: diphenylamine, (C₆H₅)₂NH2°1yes
  2. So. The primary amines A and C and the secondary amine E react, while the tertiary amines B and D do not. The answer is (a).

The idea to keep. Hinsberg's test sorts amines by the H on nitrogen: 1° and 2° amines react, 3° amines do not. The 1° sulphonamide dissolves in alkali, the 2° one does not.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Amines & Diazonium Salts

Asked about 170 times in JEE Main since 2020. This question is from 2025.