JEE Main 2021 · 26 February · evening · Single correct · +4 / −1

Match List - I with List - II.
Choose the correct answer from the options given below :

List - IList - II
(a)Siderite(i)Cu
(b)Calamine(ii)Ca
(c)Malachite(iii)Fe
(d)Cryolite(iv)Al
(v)Zn
  1. (a) (a) → (i), (b) → (ii), (c) → (iii), (d) → (iv)
  2. (b) (a) → (iii), (b) → (i), (c) → (v), (d) → (ii)
  3. (c) (a) → (i), (b) → (ii), (c) → (v), (d) → (iii)
  4. (d) (a) → (iii), (b) → (v), (c) → (i), (d) → (iv)
Answer and solution

Answer (d) (a) → (iii), (b) → (v), (c) → (i), (d) → (iv)

Solution

Chemistry ma’am · 3 steps

Write the formula of each ore first, and the metal stares right back at you from it.

  1. Recall the formulae. Each name in List - I is a common ore. Once you write its chemical formula, the metal it is mined for is the main metal atom in that formula.
    OreFormulaMetal
    SideriteFeCO₃Fe, (iii)
    CalamineZnCO₃Zn, (v)
    MalachiteCuCO₃.Cu(OH)₂Cu, (i)
    CryoliteNa₃AlF₆Al, (iv)
  2. Leftover entry. Ca, (ii), matches none of these ores. It is only there as a distractor.
  3. So. The matching is (a) → (iii), (b) → (v), (c) → (i), (d) → (iv), which is option (d).

The idea to keep. Learn ores as name plus formula, never name alone. Siderite and calamine are carbonates of Fe and Zn, malachite is a basic copper carbonate, and cryolite is Na₃AlF₆.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 80 times in JEE Main since 2020. This question is from 2021.