JEE Main 2021 · 17 March · evening · Single correct · +4 / −1

Match List - I with List - II :
Choose the correct answer from the options given below :

List - IList - II
(a)Haematite(i)Al₂O₃ . xH₂O
(b)Bauxite(ii)Fe₂O₃
(c)Magnetite(iii)CuCO₃ . Cu(OH)₂
(d)Malachite(iv)Fe₃O₄
  1. (a) (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
  2. (b) (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
  3. (c) (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
  4. (d) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Answer and solution

Answer (b) (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)

Solution

Chemistry ma’am · 3 steps

Two iron oxides here: haematite is the red Fe₂O₃, magnetite is the magnetic Fe₃O₄.

  1. Sort by metal. Haematite and magnetite are iron ores, bauxite is the aluminium ore, and malachite is a copper ore. That splits List II at once: the two iron oxides, one aluminium oxide and one copper carbonate.
  2. Tell the irons apart. Haematite (from the Greek for blood) is red Fe₂O₃, with iron only in the +3 state. Magnetite is the black, magnetic mixed oxide Fe₃O₄, which is FeO.Fe₂O₃.
    OreMetalFormulaMatch
    (a) HaematiteFeFe₂O₃(ii)
    (b) BauxiteAlAl₂O₃.xH₂O(i)
    (c) MagnetiteFeFe₃O₄(iv)
    (d) MalachiteCuCuCO₃.Cu(OH)₂(iii)
  3. So. The matching is (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii), which is option (b).

The idea to keep. Learn ores in pairs of name and formula, grouped by metal. For iron: haematite Fe₂O₃, magnetite Fe₃O₄, siderite FeCO₃, iron pyrites FeS₂.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 80 times in JEE Main since 2020. This question is from 2021.