JEE Main 2023 · 25 January · morning · Single correct · +4 / −1

A car is moving with a constant speed of 20 m/s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be : (Take g = 10 m/s²)

  1. (a) π/2
  2. (b) π/6
  3. (c) π/4
  4. (d) π/3
Answer and solution

Answer (c) π/4

Solution

Physics sir · 4 steps

The string tilts until its horizontal pull supplies exactly the centripetal force the bob needs.

  1. Forces on the bob. Only two forces act on the bob: the tension T along the string and its weight mg downwards. The bob moves in the same circle as the car, so it needs a centripetal force mv²/r pointing towards the centre.
  2. Split the tension. The vertical part balances the weight: T cos θ = mg. The horizontal part provides the centripetal force: T sin θ = mv²/r.

    tan θ = v²/rg

  3. Put in numbers. tan θ = 20²/(40 × 10) = 400/400 = 1.
  4. So. θ = 45° = π/4, which is option (c).

The idea to keep. A bob hanging in a car going round a circle behaves like a conical pendulum: tan θ = v²/rg. The mass and the string length do not matter.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Circular Motion

Asked about 70 times in JEE Main since 2020. This question is from 2023.