JEE Main 2023 · 13 April · evening · Single correct · +4 / −1

A vehicle of mass 200 kg is moving along a levelled curved road of radius 70 m with angular velocity of 0.2 rad / s. The centripetal force acting on the vehicle is:

  1. (a) 560 N
  2. (b) 14 N
  3. (c) 2800 N
  4. (d) 2240 N
Answer and solution

Answer (a) 560 N

Solution

Physics sir · 4 steps

You are given ω, not v, so use F = mω² r directly and remember to square ω.

  1. Pick the formula. Centripetal force is F = mv²/r. With v = ω r, this becomes F = mω² r, which uses the angular velocity you are given.

    F = mω² r = 200 × (0.2)² × 70

  2. Put in numbers. (0.2)² = 0.04, so F = 200 × 0.04 × 70 = 8 × 70 = 560 N.
  3. Check with speed. The speed is v = ω r = 0.2 × 70 = 14 m s⁻¹. Then mv²/r = (200 × 196)/70 = 560 N as well.
  4. So. The centripetal force on the vehicle is 560 N, option (a).

The idea to keep. Centripetal force is mω² r or mv²/r. Pick the form that matches the data, and always square the speed or the angular velocity.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Circular Motion

Asked about 70 times in JEE Main since 2020. This question is from 2023.