JEE Main 2023 · 13 April · evening · Single correct · +4 / −1
A vehicle of mass 200 kg is moving along a levelled curved road of radius 70 m with angular velocity of 0.2 rad / s. The centripetal force acting on the vehicle is:
- (a) 560 N
- (b) 14 N
- (c) 2800 N
- (d) 2240 N
Answer and solution
Answer (a) 560 N
Solution
Physics sir · 4 steps
You are given ω, not v, so use F = mω² r directly and remember to square ω.
- Pick the formula. Centripetal force is F = mv²/r. With v = ω r, this becomes F = mω² r, which uses the angular velocity you are given.
F = mω² r = 200 × (0.2)² × 70
- Put in numbers. (0.2)² = 0.04, so F = 200 × 0.04 × 70 = 8 × 70 = 560 N.
- Check with speed. The speed is v = ω r = 0.2 × 70 = 14 m s⁻¹. Then mv²/r = (200 × 196)/70 = 560 N as well.
- So. The centripetal force on the vehicle is 560 N, option (a).
The idea to keep. Centripetal force is mω² r or mv²/r. Pick the form that matches the data, and always square the speed or the angular velocity.
Answer from the NTA final answer key. Solution by PrepWiser.