JEE Main 2024 · 29 January · morning · Single correct · +4 / −1

If the radius of curvature of the path of two particles of same mass are in the ratio 3: 4, then in order to have constant centripetal force, their velocities will be in the ratio of :

  1. (a) 1: √3
  2. (b) 2: √3
  3. (c) √3: 2
  4. (d) √3: 1
Answer and solution

Answer (c) √3: 2

Solution

Physics sir · 3 steps

Same mass and same force means v² must grow in step with r, so v goes as √r.

  1. Centripetal force. A particle moving on a curve of radius r with speed v needs a force toward the centre of F = mv²/r.
  2. Fix F and m. Both F and m are the same for the two particles, so v²/r must be the same too. That means v² ∝ r, or v ∝ √r.

    v₁/v₂ = √(r₁/r₂) = √(3/4) = √3/2

  3. So. The velocities are in the ratio √3 : 2, which is option (c).

The idea to keep. For a fixed centripetal force on a fixed mass, v ∝ √r: a wider curve needs a higher speed. Write the formula, hold the fixed quantities constant, and read off the proportionality.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Circular Motion

Asked about 70 times in JEE Main since 2020. This question is from 2024.