JEE Main 2020 · 7 January · morning · Single correct · +4 / −1

The relative strength of interionic/intermolecular forces in decreasing order is :

  1. (a) dipole-dipole > ion-dipole > ion-ion
  2. (b) ion-dipole > dipole-dipole > ion-ion
  3. (c) ion-dipole > ion-ion > dipole-dipole
  4. (d) ion-ion > ion-dipole > dipole-dipole
Answer and solution

Answer (d) ion-ion > ion-dipole > dipole-dipole

Solution

Chemistry ma’am · 3 steps

Ask how much charge each partner carries: two full charges beat one full charge, which beats none.

  1. Full or partial charge. An ion carries a full charge, such as +1 or -1. A polar molecule carries only partial charges, δ+ and δ-, at its two ends. The more charge on each partner, the stronger the attraction between them.
    InteractionCharges attractingStrength
    Ion-ionfull charge with full chargestrongest
    Ion-dipolefull charge with partial chargein between
    Dipole-dipolepartial charge with partial chargeweakest
  2. How fast they fade. Distance gives the same order. Ion-ion attraction varies as 1/r, ion-dipole as 1/r² and dipole-dipole as 1/r³. So the attraction between partial charges also dies away fastest as the particles move apart.
  3. So. The decreasing order is ion-ion > ion-dipole > dipole-dipole, which is option (d).

The idea to keep. Rank electrostatic forces by the charge on each partner: full with full, then full with partial, then partial with partial. More charge means a stronger pull.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Chemical Bonding & Molecular Structure

Asked about 210 times in JEE Main since 2020. This question is from 2020.