JEE Main 2020 · 7 January · morning · Single correct · +4 / −1
The relative strength of interionic/intermolecular forces in decreasing order is :
- (a) dipole-dipole > ion-dipole > ion-ion
- (b) ion-dipole > dipole-dipole > ion-ion
- (c) ion-dipole > ion-ion > dipole-dipole
- (d) ion-ion > ion-dipole > dipole-dipole
Answer and solution
Answer (d) ion-ion > ion-dipole > dipole-dipole
Solution
Chemistry ma’am · 3 steps
Ask how much charge each partner carries: two full charges beat one full charge, which beats none.
- Full or partial charge. An ion carries a full charge, such as +1 or -1. A polar molecule carries only partial charges, δ+ and δ-, at its two ends. The more charge on each partner, the stronger the attraction between them.
Interaction Charges attracting Strength Ion-ion full charge with full charge strongest Ion-dipole full charge with partial charge in between Dipole-dipole partial charge with partial charge weakest - How fast they fade. Distance gives the same order. Ion-ion attraction varies as 1/r, ion-dipole as 1/r² and dipole-dipole as 1/r³. So the attraction between partial charges also dies away fastest as the particles move apart.
- So. The decreasing order is ion-ion > ion-dipole > dipole-dipole, which is option (d).
The idea to keep. Rank electrostatic forces by the charge on each partner: full with full, then full with partial, then partial with partial. More charge means a stronger pull.
Answer from the NTA final answer key. Solution by PrepWiser.