For reaction
The correct order of set of reagents for the above conversion is :

Solution

Chemistry ma’am · 5 steps

Block the para position with -SO₃H first, and bromine has nowhere to go but ortho.

1. Block para. Aniline with H₂SO₄, on heating, gives sulphanilic acid. The -SO₃H group now sits at the para position, so that position is taken.
2. Tame the ring. Ac₂O turns -NH₂ into -NHCOCH₃. This group still directs to ortho and para, but it activates the ring much less, so bromine adds only once instead of three times.
3. Brominate ortho. With para blocked, Br₂ goes to a position ortho to -NHCOCH₃. You get one Br, placed next to the nitrogen.
4. Remove helpers. Heating with water in acid hydrolyses the amide back to the amine. It also removes -SO₃H, because sulphonation is reversible. The amine comes out as its anilinium salt, and NaOH releases free o-bromoaniline.
5. So. The order is block, protect, brominate, deprotect, neutralise: H₂SO₄, Ac₂O, Br₂, H₂O(Δ), NaOH. That is option (b).

The idea to keep. To put a group ortho on a strongly o/p-directing ring, block para with -SO₃H and remove it at the end. Acetylation stops an amine ring from multiple substitution.

Answer from the NTA final answer key. Solution by PrepWiser.