JEE Main 2022 · 27 July · morning · Single correct · +4 / −1

Match List I with List II.
Choose the correct answer from the options given below:

List IList II
(A)Benzenesulphonyl chloride(I)Test for primary amines
(B)Hoffmann bromamide reaction(II)Anti Saytzeff
(C)Carbylamine reaction(III)Hinsberg reagent
(D)Hoffmann orientation(IV)Known reaction of Isocyanates.
  1. (a) A-IV, B-III, C-II, D-I
  2. (b) A-IV, B-II, C-I, D-III
  3. (c) A-III, B-IV, C-I, D-II
  4. (d) A-IV, B-III, C-I, D-II
Answer and solution

Answer (c) A-III, B-IV, C-I, D-II

Solution

Chemistry ma’am · 2 steps

Pin each name to one fact: Hinsberg is a reagent, and the isocyanate sits in the middle of bromamide.

  1. Match by identity. Each item in List I has one defining fact. Write that fact down first, and the matching List II entry follows from it.
    List IWhat it really isList II
    (A) Benzenesulphonyl chlorideC₆H₅SO₂Cl is the reagent that tells 1°, 2° and 3° amines apart(III) Hinsberg reagent
    (B) Hoffmann bromamide reactionRCONH₂ with Br₂ and NaOH rearranges to the isocyanate R-N=C=O, which is hydrolysed to RNH₂(IV) Known reaction of isocyanates
    (C) Carbylamine reactionRNH₂ + CHCl₃ + 3KOH gives the foul-smelling isocyanide RNC, only with primary amines(I) Test for primary amines
    (D) Hoffmann orientationHofmann elimination of quaternary ammonium hydroxides gives the less substituted alkene(II) Anti Saytzeff
  2. So. The match is A-III, B-IV, C-I, D-II, which is option (c).

The idea to keep. Tie each named reaction to one signature: Hinsberg is C₆H₅SO₂Cl, bromamide runs through an isocyanate, carbylamine tests 1° amines, Hofmann elimination is anti-Saytzeff.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Amines & Diazonium Salts

Asked about 170 times in JEE Main since 2020. This question is from 2022.