JEE Main 2020 · 5 September · evening · Single correct · +4 / −1

Reaction of ammonia with excess Cl₂ gives :

  1. (a) NH₄Cl and N₂
  2. (b) NH₄Cl and HCl
  3. (c) NCl₃ and HCl
  4. (d) NCl₃ and NH₄Cl
Answer and solution

Answer (c) NCl₃ and HCl

Solution

Chemistry ma’am · 4 steps

Ask which reactant is in excess: with chlorine left over, every H on nitrogen gets swapped for Cl.

  1. Two possible outcomes. Ammonia and chlorine give different products depending on which one is in excess. So first check which reagent is left over.
    ConditionBalanced reactionProducts
    Excess NH₃8NH₃ + 3Cl₂ → 6NH₄Cl + N₂NH₄Cl and N₂
    Excess Cl₂NH₃ + 3Cl₂ → NCl₃ + 3HClNCl₃ and HCl
  2. Excess chlorine. With plenty of Cl₂, all three H atoms on nitrogen are replaced by Cl, giving nitrogen trichloride, NCl₃, an explosive liquid. Each H removed leaves as HCl.
  3. Why no NH4Cl. NH₄Cl forms only when spare NH₃ is left to combine with HCl. Here the ammonia is used up by chlorine, so HCl stays as it is.
  4. So. Ammonia with excess chlorine gives NCl₃ and HCl, which is option (c).

The idea to keep. For NH₃ with Cl₂, excess ammonia gives NH₄Cl + N₂, and excess chlorine gives NCl₃ + HCl. NH₄Cl needs spare ammonia to form.

Answer from the NTA final answer key. Solution by PrepWiser.

Study p-Block Elements — Part II (Group 15-18)

Asked about 110 times in JEE Main since 2020. This question is from 2020.